subtraction of two numbers input from keybord via Assembly language

Bismillahir Rahmanir Rahim
At first we have to know  about some DOS function .
 Few of the functions of DOS interrupt 21h are described bellow : 
a. Function 01h : Keyboard input  Output: returns the ASCII code  of key pressed in AL       
   MOV AH, 01h
   INT   21h 
 b. Function 02h : Display a character,  whose ASCII code is in DL 
MOV AH, 02h
MOV DL, character  (character means variable name)
INT   21h  .
c. Function 09h : Print string, DS:DX  contains pointer to the character string  ending with ‘$’ or 24h (end of string marker)
 MOV AH, 09h
MOV DX,  OFFSET character
INT   21h 
d. Function 4Ch : Terminate current process   MOV AH, 4Ch and transfer controls to the invoking    MOV AL, 00h process. AL contains the return code    INT   21h

Solution:


datas      SEGMENT
aa      DB  00h   
bb DB  00h 
cc db  00h
first db "Enter your first number or Alphabat- $" 
secand db "Enter your secand number or Alphabat- $" 
datas ENDS 

staks      SEGMENT
DB         100 dup() 
staks      ENDS 

codes    SEGMENT                                          
ASSUME CS: codes, DS: datas,  SS: staks 
 Start:                                     
MOV        AX,  SEG  datas             
MOV        DS, AX              
MOV        CX,  SEG  staks             
MOV        SS, CX  

mov dx,offset first
mov ah,09
int 21h

MOV  AH, 01h ; function - input from keyboard 
INT 21h ; DOS call    ; ASCII of key pressed is in AL 
SUB al, 30h ; convert into binary 
MOV aa, al  

mov dx,offset secand
mov ah,09
int 21h

MOV  AH, 01h 
INT 21h 

SUB al, 30h 
MOV bb, al 
 
MOV  AL, aa 
MOV BL, bb 
CMP AL, BL ;AL > BL ? 
JBE ELSE_L ; No 
THEN:  ; Yes  
SUB  AL, BL  
MOV cc, AL  
JMP DISP_L 
ELSE_L:  
SUB  BL, AL  
MOV cc, BL 
DISP_L:  
MOV DL, cc  
ADD DL, 30h ; convert binary into ASCII 

MOV  AH, 02h ; call display character function 
INT 21h  ; OS call to display it             

MOV        AX, 4C00h             
INT          21h 
codes   ENDS            
 END START

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